Question #f0bdc

Question

Question #f0bdc

1 Answer

Impact of this question

1468 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-08T14:42:54

$65, 892$ $65,892$ ${yards}^{2}$ $"yards"^(2)$

Explanation:

The area of the football field will be the product of the width and the length.

The width is given as $1.20 \times 102$ $1.20 times 102$ yards.

The length is given as $5.33 \times 101$ $5.33 times 101$ yards.

Let's find the area of the football field:

$\Rightarrow A = l \times w$ $Rightarrow A = l times w$

$\Rightarrow A = (1.20 \times 102$ $Rightarrow A = (1.20 times 102$ $yards) \times (5.33 \times 101$ $"yards") times (5.33 times 101$ $yards)$ $"yards")$

$\Rightarrow A = 122.4$ $Rightarrow A = 122.4$ $yards \times 583.33$ $"yards" times 583.33$ $yards$ $"yards"$

$therefore A = 65,891.592$ $"yards"^(2)$

Therefore, the area of the football field is around $65,892$ $"yards"^(2)$ .

Science

Math

Humanities

... and beyond

Question #f0bdc

1 Answer

Explanation:

Related questions

Impact of this question