Question #de7ee

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Question #de7ee

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Answer 1 · 2016-09-28T00:11:47

Keith rented the bike for $8$ $8$ hours.

Explanation:

Let $p$ $p$ represent the price of a rental, and $h$ $h$ represent the number of hours it was rented for. Then we can represent the model given as

$p = 7 h + 18$ $p = 7h + 18$

Keith paid $74$ $74$ dollars for his rental, meaning we have $p = 74$ $p = 74$ . Our goal is to solve for $h$ $h$ . Substituting our value for $p$ $p$ into the above equation, we get

$74 = 7 h + 18$ $74 = 7h + 18$

$\Rightarrow 74 - 18 = 7 h + 18 - 18$ $=> 74 - 18 = 7h + 18 - 18$

$\Rightarrow 56 = 7 h$ $=> 56 = 7h$

$\Rightarrow \frac{56}{7} = \frac{7 h}{7}$ $=> 56/7 = (7h)/7$

$\Rightarrow 8 = h$ $=> 8 = h$

Thus Keith rented the bike for $8$ $8$ hours.

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Question #de7ee

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