Question #39e4b

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Answer 1 · 2016-10-03T01:41:52

$c \to Current strength = 2.5 A$ $c->"Current strength"=2.5A$

$t->"Time for current"=1hr20min$
$=(3600+1200)s=4800s$

$"Quantity of eletricity passed"$

$=cxxt=2.5xx4800C=12000/96500F$

The reaction at anode

$2OH^(-)-2e->H_2O+1/2O_2$

This equation reveals that 2F of electricity produces 0.5 moles $O_2$

So $12000/96500F$ electricity will produce

$1/2xx0.5xx12000/96500" moles"O_2$

Given molar volume at r.t.p is $24dm^3$ .
The volume of oxygen produced at anode will be

$=1/2xx0.5xx12000/96500xx24dm^3$

$=0.746dm^3$