If the $p H = 12$ $pH=12$ for a solution of potassium hydroxide, what is $[H O^{-}]$ $[HO^-]$ ?

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If the $p H = 12$ $pH=12$ for a solution of potassium hydroxide, what is $[H O^{-}]$ $[HO^-]$ ?

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Answer 1 · 2016-10-02T16:58:38

$[H O^{-}]$ $[HO^-]$ $=$ $=$ $0.01 \cdot m o l \cdot L^{- 1}$ $0.01*mol*L^-1$ .

Explanation:

We know, or should know that (i) $p H = - {log}_{10} [H_{3} O^{+}]$ $pH=-log_10[H_3O^+]$ , and $p O H = - {log}_{10} [H O^{-}]$ $pOH=-log_10[HO^-]$ ; and (ii), given that $K_{w} = [H_{3} O^{+}] [^{-} O H] = 10^{- 14}$ $K_w=[H_3O^+][""^(-)OH]=10^-14$ under standard conditions, $p K_{w} = p H + p O H = 14 .$ $pK_w=pH+pOH=14.$

We have $p H = - {log}_{10} [H_{3} O^{+}] = 12$ $pH=-log_10[H_3O^+]=12$ ; thus $[H_{3} O^{+}] = 10^{- 12} \cdot m o l \cdot L^{- 1}$ $[H_3O^+]=10^-12*mol*L^-1$ , and $p O H = 2$ $pOH=2$ , and thus $[H O^{-}] = 10^{- 2} \cdot m o l \cdot L^{- 1}$ $[HO^-]=10^-2*mol*L^-1$ .

What is $[K^{+} (a q)]$ $[K^+(aq)]$ ?

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If the $p H = 12$ $pH=12$ for a solution of potassium hydroxide, what is $[H O^{-}]$ $[HO^-]$ ?

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If the pH=12pH=12 for a solution of potassium hydroxide, what is [HO−][HO^-]?

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If the $p H = 12$ $pH=12$ for a solution of potassium hydroxide, what is $[H O^{-}]$ $[HO^-]$ ?