Question #5cb57

1 Answer
Jan 18, 2017

The weight of 100cm uniform bar will at the center of gravity i.e. at the middle point #G# of the bar.

A support is at the point X on the bar and this point is at a distance of 23 cm from one end A from which an unknown weight #Wkg# is hanged to balance the system.

Here #XA=23cm and XG=(50-23)=27cm#

Considering the moments of the weight #Wkg# and weight of the bar about X we can write

#"weight of bar"xxXG=WxxXA#

#=>17.2xx27=Wxxxx23#

#=>W=20.2cm#