What is the reaction between potassium hydroxide and $1, 2 - C_{6} H_{4} (O C (= O) C H_{3}) (C O_{2} H)$ $1,2−C_6H_4(OC(=O)CH_3)(CO_2H)$ ?

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What is the reaction between potassium hydroxide and $1, 2 - C_{6} H_{4} (O C (= O) C H_{3}) (C O_{2} H)$ $1,2−C_6H_4(OC(=O)CH_3)(CO_2H)$ ?

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Answer 1 · 2016-10-10T19:16:47

This is a representation of aspirin, $1, 2 - C_{6} H_{4} (O (O =) C - C H_{3}) (C O_{2} H)$ $1,2-C_6H_4(O(O=)C-CH_3)(CO_2H)$ , which would undergo an acid base reaction with $K O H (a q)$ $KOH(aq)$

Explanation:

$1, 2 - C_{6} H_{4} (O (O =) C - C H_{3}) (C O_{2} H) + K O H \to$ $1,2-C_6H_4(O(O=)C-CH_3)(CO_2H) + KOHrarr$

$1, 2 - C_{6} H_{4} (O (O =) C - C H_{3}) (C O_{2}^{-} K^{+}) + H_{2} O$ $1,2-C_6H_4(O(O=)C-CH_3)(CO_2^(-)K^+) + H_2O$

Aspirin is in fact one of the most useful drugs known to modern medicine, and is currently widely used in low doses in order to prevent heart disease.

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What is the reaction between potassium hydroxide and $1, 2 - C_{6} H_{4} (O C (= O) C H_{3}) (C O_{2} H)$ $1,2−C_6H_4(OC(=O)CH_3)(CO_2H)$ ?

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What is the reaction between potassium hydroxide and 1,2−C6H4(OC(=O)CH3)(CO2H)1,2−C_6H_4(OC(=O)CH_3)(CO_2H)?

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What is the reaction between potassium hydroxide and $1, 2 - C_{6} H_{4} (O C (= O) C H_{3}) (C O_{2} H)$ $1,2−C_6H_4(OC(=O)CH_3)(CO_2H)$ ?