What would occur in the reaction between potassium permanganate, KMnO4 and sodium sulfite, Na2SO3?

1 Answer
Oct 6, 2016

A redox reaction occurs. Sulfite should be oxidized to sulfate. Permanganate ion should be reduced to Mn2+.

Explanation:

Reduction half equation: Mn(VII+)Mn(II+)

MnO4+8H++5eMn2++4H2O (i)

Oxidation half equation: S(IV+)S(VI+)

SO23+H2OSO24+2H++2e (ii)

Both equations are (I think) balanced with respect to mass and charge, as they must be if they reflect reality. The overall redox reaction excludes the electrons; so we take 2×(i)+5×(ii):

2MnO4+5SO23+6H+2Mn2++5SO24+3H2O

Which is (I think) balanced with respect to mass and charge.

So what would you observe in this reaction? MnO4 is strongly coloured, and gives a beautiful deep purple solution. On the other hand, Mn2+ is almost colourless (very concentrated solutions are a pale rose). And thus this redox reaction is self-indicating, and proposes that 2 equiv permanganate reacts with 5 equiv of sulfite.

How did I know the oxidation/reduction products? Experience and practice, and actually doing the titrations and observing and explaining the colour change.