Question #d590d

1 Answer
Oct 6, 2016

Seth bought 24 feet and Luke bought 27 feet of fencing

Explanation:

Let
XXXLL be the length of Luke's garden
XXXWL be the width of Luke's garden
XXXAL we the area of Luke's garden
XXXLS the the length of Seth's garden
XXXWS be the width of Seth's garden
XXXAS be the area of Seth's garden

Since we are told Seth's garden is square
XXXLS=WS
and
XXXAS=(LS)2
Further we are told that
XXXLS=LL3
So
XXXAS=(LL3)2=L2L6LL+9

We are also told that
XXXWL=LL2
So
XXXAL=LL×WL=L2L2

Since the areas are equal
XXXL2L6LL+9=L2L2

XXX2L2L12LL+18=L2L

XXXL2L12LL+18=0

XXX(LL9)(LL3)=0
and
either LL=9 or LL=3
Since LS=LL3 and assuming Seth's garden is not 0 feet long
LL=3 must be extraneous
XXXLL=9

Luke's garden
Since WL=LL2
the perimeter of Luke's garden must be
XXX2×(9+92)=27 feet.

Seth's garden
Since LS=LL3LS=6
and LS=WS
the perimeter of Seth's garden must be
XXX2×(6+6)=24 feet