Question #18870

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Question #18870

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Answer 1 · 2016-10-11T06:43:49

Given $Y = 32 % and X = (100 - 32) % = 68 %$ $Y=32% and X= (100-32)%=68%$

Dividing the each percentage composition by respective atomic mass and taking their ratio ,we get the ratio of no. of atoms of X and Y as

$X : Y = \frac{68}{50} : \frac{32}{16} = 1.36 : 2$ $X:Y=68/50:32/16=1.36:2$

$= \frac{1.36}{1.36} : \frac{2}{1.36} \approx 1 : 1.5 = 2 : 3$ $=1.36/1.36:2/1.36~~1:1.5=2:3$

Hence the formula $X_{2} Y_{3}$ $X_2Y_3$

NB: I think,the atomic mass of X should be 51.This would give the same result with easier calculation. Actually the atomic mass of Vanadium is $\approx 51$ $~~51$ .This has +3 state.

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