What mole is occupied by 1*mol of gas under standard conditions?

1 Answer
Dec 27, 2016

V=22.4*dm^3

Explanation:

V=(nRT)/P

V=(1*cancel(mol)xx0.0821*L*cancel(atm)*cancel(K^-1)*cancel(mol^-1)xx273*cancelK)/(1*cancel(atm))

=22.4*L or 22.4*dm^3

Note that 1*dm^3=(1xx10^-1*m)^3=1xx10^-3m^3=1*L, i.e. 1*L=1*dm^3=10^-3m^3.