Question #b4dc0
1 Answer
The answer is (B)
Explanation:
The idea here is that the partial pressures of the two gases will be proportional to the number of moles each gas contributes to the total number of moles present in the container.
You can take the molar masses of the two gases to be
#M_ ("M CH"_ 4) = "16 g mol"^(-1)#
#M_( "H"_ 2) = "2 g mol"^(-1)#
This means that for equal masses of methane and hydrogen gas, let's say
#m color(red)(cancel(color(black)("g"))) * "1 mole CH"_4/(16color(red)(cancel(color(black)("g")))) = (m/16)" moles CH"_4#
#m color(red)(cancel(color(black)("g"))) * "1 mole H"_2/(2color(red)(cancel(color(black)("g")))) = (m/2)" moles H"_2#
Now, the partial pressure of a gas that's part of a gaseous mixture, as given by Dalton's Law of Partial Pressures, is equal to
#color(purple)(bar(ul(|color(white)(a/a)color(black)(P_"gas i" = "moles of i"/"total moles of gas" xx P_"total")color(white)(a/a)|)))#
The ratio between the number of moles of gas
In this case, the total number of moles of gas present in the mixture is
#(m/16)" moles" + (m/2)" moles" = ((9m)/16)" moles"#
This means that the mole fraction of hydrogen gas will be
#chi_( "H"_ 2) = ( color(red)(cancel(color(black)(m)))/2 color(red)(cancel(color(black)("moles"))))/((9color(red)(cancel(color(black)(m))))/16 color(red)(cancel(color(black)("moles")))) = 1/2 * 16/9 = color(green)(bar(ul(|color(white)(a/a)color(black)(8/9)color(white)(a/a)|)))#
This means that for a total pressure
#P_( "H"_ 2) = 8/9 xx P_"total"#