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Answer 1 · 2018-01-05T17:35:54

The new volume is $= 4.17 L$ $=4.17L$

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ at constant temperature

The initial pressure is $P_{1} = 100 k P a$ $P_1=100kPa$

The initial volume is $V_{1} = 9 L$ $V_1=9L$

The final pressure is $P_{2} = 216 P a$ $P_2=216Pa$

The final volume is

$V_{2} = \frac{P_{1}}{P_{2}} \cdot V_{1} = \frac{100}{216} \cdot 9 = 4.17 L$ $V_2=P_1/P_2*V_1=100/216*9=4.17L$