Q1
Given Molar mass of the gas 146" g/mol"
By Ideal gas law we know
PV=w/MRT
where
P->"Pressure of the gas"=1atm
V->"Volume of the gas"
R->"Universal gas constant"=0.082LatmK^-1mol^-1
T->"Temperature of the gas in K"=(150+273)K=423K
w->"Mass of the gas"
M->"Molar mass of the gas"=146" g/mol"
PV=w/MRT
=>P=(w/V)/MRT=D/MxxRT
" where " D="Density of the gas at given temperature and pressure"
So
D=(PM)/(RT)
Inserting values we have
=>D=(PM)/(RT)=(1xx146)/(0.082xx423)=4.21g/L
Q2
By ideal gas law we have
(P_1V_1)/T_1=(P_2V_2)/T_2......(2)
Given
P_1->"Initial pressure"=73 cm=73/760atm
T_1->"Initial Temperature"=68^@F=xK
(x-273)/(373-273)=(68-32)/(212-32)
=>x=36/180xx100+273=293K
V_1->"Initial Volume"=875mL=0.875L
P_2->"Final pressure"=12atm
T_2->"Finial Temperature"=350K
V_2->"Final Volume"=?
Inserting values in equation (2)
(P_1V_1)/T_1=(P_2V_2)/T_2
=>(P_2V_2)/T_2=(P_1V_1)/T_1
=>V_2=(P_1V_1T_2)/(P_2T_1)
=>V_2=(73/760xx0.875xx350)/(12xx293)L~~0.0084L=8.4mL
