Ethylene reacts to give $C_{2} H_{4} O_{2}$ $C_2H_4O_2$ ...what is the product?

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Ethylene reacts to give $C_{2} H_{4} O_{2}$ $C_2H_4O_2$ ...what is the product?

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Answer 1 · 2017-01-05T18:41:26

Can you tell us what the product is?

Explanation:

Now, clearly, the $C_{2} H_{4}$ $C_2H_4$ reactant is $ethylene$ $"ethylene"$ , $H_{2} C = C H_{2}$ $H_2C=CH_2$ .

But the $C_{2} H_{4} O_{2}$ $C_2H_4O_2$ product could be $acetic acid$ $"acetic acid"$ , $H_{3} C - C O_{2} H$ $H_3C-CO_2H$ ; it could be $1,2-dioxetane$ $"1,2-dioxetane"$ , a cyclic peroxide; it could be a cyclic ether. Unless you specify the product, we cannot suggest its synthesis.

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Ethylene reacts to give $C_{2} H_{4} O_{2}$ $C_2H_4O_2$ ...what is the product?

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Ethylene reacts to give C2H4O2C_2H_4O_2...what is the product?

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Ethylene reacts to give $C_{2} H_{4} O_{2}$ $C_2H_4O_2$ ...what is the product?