Question

Question #4f14c

Answer 1

Molecular formula of Cadaverine is `C_5H_14N_2`

Explanation:

Given

Cadaverine contains 58.55% C, 13.81% H, and 27.40% N by mass, and has a molar mass of 102.2 g/mol.

Considering atomic masses as follows

`C->12" g/mol"`

`H->1" g/mol"`

`N->14" g/mol"`

Dividing the percentage of C,H and N by respective atomic mass and taking their ratio we get the ratio of number of atoms of C,H and N in the molecule of Cadaverine as follows

`n_C:n_H:n_N=58.55/12:13.81/1:27.40/14`
`=4.88:13.81:1.96`

`=4.88/1.96:13.81/1.96:1.96/1.96`

`~~2.5:7:1=5:14:2`

So empirical formula of Cadaverine is `C_5H_14N_2`

Let its molecular formula be `(C_5H_14N_2)_n`

By this formula its molar mass is `(5*12+14*1+2*14)n=102n" g/mol"`

Equating this with the given molar mass we get

`102n=102.2=>n~~1`

So molecular formula of Cadaverine is `C_5H_14N_2`