Question

Question #b97d6

Answer 1

Atomic mass of element A be `=43.6" g/mol"`

Explanation:

Let atomic mass of element A be `=a" g/mol"`
Again atomic mass of Oxygen `=16" g/mol"`

So molar mass of the compound `A_2O_3=(2a+48)" g/mol"`
One molecule of the compound `A_2O_3` contains 2 atoms .

So the ratio of mass of `A` and mass of `A_2O_3` in a molecule
`=(2a)/(2a+48)`

Again it is given that 0.359 grams of A reacts to give 0.559 grams of the compound. So we can write

`(2a)/(2a+48)=0.359/0.559`

`=>a/(a+24)=359/559`

`=>1+24/a=559/359=1.55`

`=>24/a=0.55`

`=>a=24/0.55=43.6`