Question #bde13

Question

1250 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-22T15:44:14

Showing calculation only

given

#w=2.08g#

#M=28" g/mol "->"for "N_2#

#R=0.08206LatmK^-1mol^-1#

#T=50+273.15=323.15K#

#V=0.285L#

#P=w/M(RT)/V=2.08/28xx(0.08206xx323.15)/0.285atm~~6.9atm#