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Question #bd799

1 Answer

Oct 27, 2016

$f (a + h) = 3 {(a + h)}^{2} + 2$ $f(a+h) = 3(a+h)^2 + 2$ or $f (a + h) = 3 a^{2} + 6 a h + 3 h^{2} + 2$ $f(a + h) = 3a^2 + 6ah + 3h^2 + 2$

Explanation:

To solve this problem you need to substitute $(a + h)$ $(a + h)$ into the equation for everywhere in the equation there is an $x$ $x$ or:

$f (a + h) = 3 {(a + h)}^{2} + 2$ $f(a+h) = 3(a+h)^2 + 2$

If you want to expand this would equal:

$f (a + h) = 3 (a + h) (a + h) + 2$ $f(a + h) = 3(a + h)(a + h) + 2$

$f (a + h) = 3 (a^{2} + 2 a h + h^{2}) + 2$ $f(a + h) = 3(a^2 + 2ah + h^2) +2$

$f (a + h) = 3 a^{2} + 6 a h + 3 h^{2} + 2$ $f(a + h) = 3a^2 + 6ah + 3h^2 + 2$

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