Question #262d6

1 Answer
P dilip_k
Oct 26, 2016

By ideal gas law we know

#PV=w/MRT#

#=>P=w/V*(RT)/M#

#=>P=d*(RT)/M#

#=>d=(MP)/(RT)#

Where

#d->"Density of gas"#

#P->"Pressure of gas"=898mm=898/760atm#

#M->"Molar mass Argon"=39.948" g/mol"#

#T->"Temperature of gas"=53^@C=326K#

#R->"Ideal gas constant"=0.082LatmK^-1mol^-1#

So Density

#d=(39.948g/"mol"xx898/760atm)/(0.082(Latm)/(Kmol)xx326K)#

#=>d~~1.77g/L#

Related questions
See all questions in Ideal Gas Law
Impact of this question
1351 views around the world
You can reuse this answer
Creative Commons License