Question #ee169

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Question #ee169

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Answer 1 · 2016-10-30T00:39:11

You have done well except molar mass of hydrogen gas $H_{2}$ $"H"_2$ , should be doubled as it has two atoms. The answer goes as below

Explanation:

Use the formula
Density $d = Molar mass \times \frac{P}{R T}$ $d = "Molar mass"xx P / (RT)$

$Molar mass = 2 \times 1.00794 = 2.01588 g$ $"Molar mass" = 2xx1.00794= 2.01588g$
$P = 1645 \times 0.068046 = 111.93567 a t m$ $P = 1645 xx 0.068046 = 111.93567 atm$
$R = 0.08206$ $R = 0.08206$
$T = 273.15 + 24.0 = 297.15 K$ $T = 273.15 + 24.0 = 297.15 K$

Inserting the values in the formula:

$d = 2.01588 \times \frac{111.93567}{0.08206 \times 297.15}$ $d = 2.01588xx 111.93567 / (0.08206xx297.15)$

$d = 9.2 g / L$ $d = 9.2 g//L$ , rounded to one decimal place.

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Question #ee169

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