Question #1e174

Question

1529 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-01T02:23:43

#y=1/(sqrt(2x-1))#

#y^-1=sqrt(2x-1)#

#y^-2=2x-1#

#-2y^-3*(dy)/(dx)=2#

#-y^-3*(dy)/(dx)=1#

#-1/y^3*(dy)/(dx)=1#

Multiply both sides of the equation by #-y^3#...

#(dy)/(dx)=-y^3#

#(dy)/(dx)=-(1/(sqrt(2x-1)))^3#