A flexible container holds $6.70 mol$ $"6.70 mol"$ of a gas. An additional $3.50 mol$ $"3.50 mol"$ of the gas is added to the container until it reaches a final volume of $25.4 L$ $"25.4 L"$ while temperature and pressure are kept constant, what was the initial volume?

Question

A flexible container holds $6.70 mol$ $"6.70 mol"$ of a gas. An additional $3.50 mol$ $"3.50 mol"$ of the gas is added to the container until it reaches a final volume of $25.4 L$ $"25.4 L"$ while temperature and pressure are kept constant, what was the initial volume?

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Answer 1 · 2016-11-05T07:58:59

The initial volume was 16.7 L.

Explanation:

This problem requires Avogadro's law, which states that the amount (moles) of a gas is directly proportional to its volume, such that if the amount increases, the volume increases and vice versa. You correctly determined the formula to use: $\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$ $V_1/n_1=V_2/n_2$

Known
$n_{1} = 6.70 mol$ $n_1="6.70 mol"$
$V_{2} = 25.4 L$ $V_2="25.4 L"$
$n_{2} = 6.70 mol+3.50 mol = 10.2 mol$ $n_2="6.70 mol+3.50 mol"="10.2 mol"$

Unknown
$V_{1}$ $V_1$

Solution
Rearrange the equation to isolate $V_{1}$ $V_1$ . Substitute the known values into the equation and solve.

$V_{1} = \frac{V_{2} n_{1}}{n_{2}}$ $V_1=(V_2n_1)/n_2$

$V_1=(25.4"L"xx6.70cancel"mol")/(10.2cancel"mol")="16.7 L"$ rounded to three significant figures

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A flexible container holds $6.70 mol$ $"6.70 mol"$ of a gas. An additional $3.50 mol$ $"3.50 mol"$ of the gas is added to the container until it reaches a final volume of $25.4 L$ $"25.4 L"$ while temperature and pressure are kept constant, what was the initial volume?

1 Answer

Explanation:

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Humanities

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A flexible container holds "6.70 mol"6.70 mol"6.70 mol" of a gas. An additional "3.50 mol"3.50 mol"3.50 mol" of the gas is added to the container until it reaches a final volume of "25.4 L"25.4 L"25.4 L" while temperature and pressure are kept constant, what was the initial volume?

1 Answer

Explanation:

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Impact of this question

A flexible container holds $6.70 mol$ $"6.70 mol"$ of a gas. An additional $3.50 mol$ $"3.50 mol"$ of the gas is added to the container until it reaches a final volume of $25.4 L$ $"25.4 L"$ while temperature and pressure are kept constant, what was the initial volume?