Question #af2a7

1 Answer
Oct 20, 2017

Option (D) is correct

Explanation:

drawn

Let us consider a sector of XOY of a circle of radius r which has been formed by an arc of length S. This arc subtends angle theta radian at the center O of the circle.

Now S/r=theta

=>S=rtheta....[1]

Let the perimeter of the sector P=S+2r......[2]

Combining [1] and [2] we get

P=rtheta +2

=>r=P/(theta+2).....[3]

Now area of the sector A=(pir^2)/(2pi)xxtheta

=>A=r^2/2xxtheta.....[4]

Combining [3] and [4] we get

A=1/2xxP^2/(theta+2)^2xxtheta

Now

A=P^2/2xxtheta/(theta^2+4theta+4)

=>A=P^2/2xx1/(theta+4+4/theta)

=>A=P^2/2xx1/((sqrttheta-2/sqrttheta)^2+8).....[5]

By the given condition the perimeter P of the sector is fixed or constant . So A will be maximum when denominator of the RHS of [5] is minimum and this is possible only when

(sqrttheta-2/sqrttheta)=0

=>theta =2 radian

Hence option (D) is correct