Question #96660 Physics Forces and Newton's Laws Frictional Forces 1 Answer MattyMatty Dec 14, 2017 F=12,525N (answer C) Explanation: x=v0t+at22 v=v0+at v=0⇒t=−v0a⇒x=−v202a 3022a=−53.5 ⇒a=−8.41ms2 2022a=−23.9 ⇒a=−8.37ms2 1022a=−6.1 ⇒a=−8.20ms2 ⇒a=−8.35ms2 ⇒F=ma=1,500⋅8.35=12,525N Answer link Related questions Question #d6539 Question #242b7 Question #6bde4 Question #50c79 Question #a2018 Question #f7a62 Question #27931 Question #0b375 Question #d70af Question #dab6f See all questions in Frictional Forces Impact of this question 1572 views around the world You can reuse this answer Creative Commons License