How much dihydrogen will be required to reduce completely a $1.22 \cdot m o l$ $1.22*mol$ quantity of dinitrogen gas?

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How much dihydrogen will be required to reduce completely a $1.22 \cdot m o l$ $1.22*mol$ quantity of dinitrogen gas?

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Answer 1 · 2016-11-08T17:59:09

$\frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g) \to N H_{3} (g)$ $1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)$

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Given the stoichiometry, precisely $3.66 \cdot m o l$ $3.66*mol$ dihydrogen gas are required to give ammonia. Each equiv dinitrogen requires three equiv dihydrogen. How much ammonia gas would be produced given complete reaction (an unlikely scenario)?

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How much dihydrogen will be required to reduce completely a $1.22 \cdot m o l$ $1.22*mol$ quantity of dinitrogen gas?

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How much dihydrogen will be required to reduce completely a 1.22⋅mol1.22*mol quantity of dinitrogen gas?

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How much dihydrogen will be required to reduce completely a $1.22 \cdot m o l$ $1.22*mol$ quantity of dinitrogen gas?