Question #b9d73

1 Answer
anor277
Nov 9, 2016

Well, my bet is on #Bu^(t)Cl#, as it has the least possibility of dispersion forces.

Explanation:

On the other hand, #"n-butyl choride"# has the longest hydrocarbyl chain, and therefore should be the least volatile because of chain/chain interactions.

Having said all of this, it is up to you to look up the boiling points of the isomeric butyl chlorides. As a scientist, you should always consider the data first.

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