Question #6e4c9

1 Answer
Nov 13, 2016

Mrs. Hill's son is 15 1/31513 years old.

Explanation:

Let Mrs. Hill's age = hh
Let her son's age = ss

From the problem, the two equations are:
h=4+2sh=4+2s
h+s=50h+s=50

We can solve for this using substitution because one of the variables is already isolated.
(4+2s)+s=50(4+2s)+s=50

Simplify and solve for the son's age (ss):
2s+s+4=502s+s+4=50
3s+4=503s+4=50
3s=463s=46
s=15.33s=15.33 years old

Plug the son's age into one of the original equations:
h=4+2(15.33)h=4+2(15.33)
h=34.67h=34.67 years old

Check:
"Mrs. Hill is 4 year older than twice her son's age. If the sum of their ages is 50, how old is her son?"
34 1/33413 is 4 more than 2 times 15 1/31513. 34 2/3+15 1/33423+1513 is 50.