Question #ead50

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Answer 1 · 2016-11-15T15:24:19

The point $(- 4, 0)$ $(-4,0)$

$x$ $x$ intercept is when $y = 0$ $y=0$

substitute $0$ $0$ instead of $y$ $y$ and then solve for $x$ $x$

$- 3 x + 8 (0) = 12$ $-3x+8(0)=12$
$- 3 x = 12$ $-3x=12$
$x = - 4$ $x=-4$

The point is $(- 4, 0)$ $(-4,0)$

Answer 2 · 2016-11-15T15:25:44

The x-intercept= -4
$(- 4, 0)$ $(-4,0)$

To find the x-intercept of a graph, make $y = 0$ $y=0$

$- 3 x + 8 y = 12$ $-3x+8y = 12$

$- 3 x + 8 (0) = 12$ $-3x+8(0) = 12$

$- 3 x = 12 \leftarrow \div - 3$ $-3x= 12" "larrdiv -3$

$x = - 4$ $x =-4$