Question

What is the volume occupied by a `91.8*g` mass of carbon dioxide that is heated to `517.2*K`, and subjected to a pressure of `287*"Torr"`?

Answer 1

`V~=235*L`

Explanation:

Given the Ideal Gas equation.....`PV=nRT`

So `V=(nRT)/P`, and we know that `760*mm*Hg-=1*atm`

`V=((91.8*g)/(44.01*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx517.2*K)/((287*"Torr")/(760*"Torr"*atm^-1))=??L.`

The gas constant conveniently gives us the volume in `"litres"`.

Note here that I have (i) converted the pressure in `"Torr"`, and (ii) converted the temperature to `"degrees Kelvin"`, which are typically used in these reactions.