Question

Question #5e5f5

Answer 1

`lim_{n to infty} (3^(n+1))/(4^(n-1))=0`

Explanation:

`(3^(n+1))/(4^(n-1))=(3^n cdot 3^1)/(4^n cdot 4^-1)=3 cdot 4 cdot (3/4)^n`

`lim_{n to infty} 3 cdot 4 cdot (3/4)^n=[3 cdot 4 cdot 0]=0`