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Answer 1 · 2016-11-27T18:02:06

The answer is #=tanx#

#cscx=1/sinx#

#cotx=cosx/sinx#

#secx=1/cosx#

#cos^2x+sin^2x=1#

#tanx=sinx/cosx#

#(cscx-cotx)(secx+1)=(1/sinx-cosx/sinx)(1/cosx+1)#

#=((1-cosx)/sinx)((1+cosx)/cosx)#

#=(1-cos^2x)/(sinxcosx)#

#=sin^2x/(sinxcosx)#

#=sinx/cosx#

#=tanx#