What volume would a 10g mass of carbon monoxide enclosed in a piston occupy at 1atm, and 0 C?

2 Answers
Nov 28, 2016

Well, one mole of ideal gas occupies 22.4 L.

Explanation:

So, we have 10g28.01gmol13mole.

And thus if we assume carbon monoxide behaves ideally, its volume (if enclosed in a piston expanding against atmospheric pressure) would be approx. 7.4L.

Nov 29, 2016

8.00 Liter

Explanation:

It can be further explained as :-

idle gas equation is

PV=nRT

Here ,

P = 1 atm
V = To be find out
R = 0.08206 Universal Gas constant
T = 273 k
n=mM
m = mass of gas [g], given 10 g
M = mass of 1 mole of gas [g] that is 28.01 of CO

By putting all values -

1V=1028.010.08206273
or
V=24.23828.01
or
V = 8.00

Hence Answer is 8.00 Liter Volume