Question #5a48c

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Question #5a48c

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Answer 1 · 2016-12-01T14:03:22

$(0, - 1), (4, 0)$ $(0,-1),(4,0)$

Explanation:

When this line crosses the y-axis the corresponding x-coordinate at this point will be zero. Substituting x = 0 into the equation of the line will give the value of the y-coordinate.

$\Rightarrow y = (0.25 \times 0) - 1 = 0 - 1 = - 1$ $rArry=(0.25xx0)-1=0-1=-1$

$\Rightarrow (0, - 1) is point on the y-axis$ $rArr(0,-1)" is point on the y-axis"$

Similarly when the line crosses the x-axis the corresponding y-coordinate at this point will be zero. Substituting y = 0 into the equation gives the value of the x-coordinate.

$\Rightarrow 0.25 x - 1 = 0 \Rightarrow 0.25 x = 1$ $rArr0.25x-1=0rArr0.25x=1$

$\Rightarrow x = \frac{1}{0.25} = 4 \Rightarrow (4, 0) is point on the x-axis$ $rArrx=1/(0.25)=4rArr(4,0)" is point on the x-axis"$

$Plot (0,-1),(4,0)$ $"Plot (0,-1),(4,0) "$ on square paper and draw a straight line through them.
graph{1/4x-1 [-10, 10, -5, 5]}

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Question #5a48c

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