What is the #100#th derivative of #2e^x#?
1 Answer
Dec 6, 2016
Well, you should memorize that the derivative of
The constant floats out front, so
#(d^n)/(dx^n)[2e^(x)]#
#= 2(d^n)/(dx^n)[e^(x)]#
#= 2e^x#
Since we just proved it in general, what does that tell you about the