Question #b5a9e

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Answer 1 · 2016-11-30T22:11:08

10 and 22 total 32 but have a difference of 12.

First, let's call our two numbers $x$ and $y$ .

We know from the problem:

$x + y = 32$

We also know:

$x - y = 12$

Next, solve the first equation for $x$ :

$x + y - y = 32 - y$

$x + 0 = 32 - y$

$x = 32 - y$

Now we can substitute $32 - y$ for $x$ in the second equation and determine the value of $y$ :

$(32 - y) - y = 12$

$32 - 2y = 12$

$32 - 32 - 2y = 12 - 32$

$0 - 2y = -2$

$-2y = -20$

$(-2y)/-2 = (-20)/(-2)$

$y = 10$

We can now substitute $10$ for $y$ in the solution for the first equation and calculate $x$ :

$x = 32 - 10$

$x = 22$