Question #2fc5b

1 Answer
Feb 10, 2017

You can do it like this:

Explanation:

The effective nuclear charge sf(Z_"eff"), experienced by an electron is less than the nuclear charge sf(Z) because of the shielding effect of the other electrons:

sf(Z_(eff)=Z-s)

Where sf(s) is the shielding constant.

We can calculate sf(s) by applying Slater's Rules:

Electrons are grouped together in increasing order of sf(n) and sf(l) values. sf(n) tells you the number of the energy level and sf(l) denotes the sub - shell such as sf(s, p, d). Because sf(s) and sf(p) electrons are close in energy they are grouped together:

sf([1s][2s,2p][3s,3p][3d][4s,4p][4d][4f][5s,5p]) and so on.

You can calculate the screening constant as follows:

Add 0.35 for each other electron within the same group, except for sf[1s] when this is 0.3

If the group is of the sf(["ns,np"]) type you add an amount of 0.85 for each electron with a principal quantum number of sf((n-1)) and an amount of 1.00 for each electron with a quantum number of sf((n-2)) or less.

For sf([d]) and sf([f]) electrons just add 1.00 for each electron which is closer to the nucleus.

Lets apply this to sf(""_25Mn):

The electron structure is:

sf([1s^(2)][2s^(2)2p^(6)][3s^(2)3p^(6)][3d^(5)][4s^(2)])

For a 3d electron:

Within the 3d group there are 4 other electrons giving 4 x 0.35 = 1.40 units.

There are 18 other electrons closer to the nucleus giving 18 x 1.00 =18.0 units.

:.sf(s=1.40+18.0=19.4) units.

:.sf(Z_(eff)=25-19.4=5.6) units.

For a 4s electron:

Within the 4s group there is 1 other electron giving 1 x 0.35 = 0.35 units.

In the (n - 1) group, which are the 3s, 3p and 3d, electrons there are 13 electrons giving 13 x 0.85 = 11.05 units

This leaves 10 (n - 2) electrons. This gives 10 x 1 = 10 units.

:.sf(s=0.35+11.05+10=21.4) units.

:.sf(Z_(eff)=25-21.4=3.6) units.

This shows that the 4s electrons experience a smaller effective nuclear charge than the 3d electrons so are more easily lost

This is consistent with observations.