If the volume of an ideal gas at 350 torr of pressure and 25C is 450 L, at what temperature is its volume 420 L and pressure 830 torr in a sealed balloon?

1 Answer

386.6 degrees C

Explanation:

V1×P1T1=V2×P2T2

V1=450
P1=350
T1=273+25=298 temperature must be calculated in degrees K or absolute zero.

V2=420
P2=830
T2=unknown?

putting these values into the equation gives

450×350298=420×830T2 Solving for T2 gives

T2=420×830×298450×350 solving gives

#T_2 = 659.57333333 subtract 273 to bring back to degrees C and round off to four significant figures. gives

T2=386.6