Question #d2ca6

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Answer 1 · 2016-12-04T22:06:50

$b = \frac{2 A}{9} - 35 = \frac{2}{9} A - 35$ $b= (2A)/9-35 = 2/9 A-35$

The formula for the area of a trapezois is $A = \frac{(b_{1} + b_{2}) h}{2}$ $A=((b_1+b_2)h)/2$ ,

where $b_{1}$ $b_1$ and $b_{2}$ $b_2$ are the lengths of the bases and $h$ $h$ is the height.

In this example,

$A = \frac{9 (b + 35)}{2}$ $A=(9(b+35))/2$ , find $b$ $b$

$2*A=(9(b+35))/cancel2 *cancel2color(white)(aaa)$ Multiply both sides by 2

$2A=9(b+35)$

$(2A)/9=(cancel9(b+35))/cancel9color(white)(aaa)$ Divide both sides by 9

$(2A)/9color(white)(aa)=b+35$

$color(white)(a)-35color(white)(aaa)-35color(white)(aaa)$ Subtract 35 from both sides

$(2A)/9-35=b$

This can also be written as $b= 2/9 A -35$