Assumption:
The question is asking for the value of #n# to be determined given that:
#" "color(brown)(8n-10<6-2n)#
#color(green)("Treat this as if it were: " 8n-10 =6-2n)#
#color(green)("In inequalities you have to turn the inequality sign round the other way")#
#color(green)("if you multiply by -1. It is NOT THE CASE in this question.")#
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Add #color(blue)(2n)# to both sides
#" "color(brown)(8ncolor(blue)(+2n)-10 < 6 -2ncolor(blue)(+2n))#
But #-2n+2n=0# giving:
#" "color(brown)(10n-10<6)#
Add #color(blue)(10)# to both sides
#" "color(brown)(10ncolor(blue)(+10)-10<6color(blue)(+10))#
#" "color(brown)(10n<16)#
Divide both sides by 10
#" "color(brown)(10/(color(blue)(10))n<16/(color(blue)(10))#
But #10/10=1#
#" "color(brown)(n<1.6)#
