Question #9c6b8

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Question #9c6b8

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Answer 1 · 2016-12-08T21:41:03

Not sure what you are asking!

$n < 1.6$ $n<1.6$

Explanation:

Assumption:

The question is asking for the value of $n$ $n$ to be determined given that:

$8 n - 10 < 6 - 2 n$ $" "color(brown)(8n-10<6-2n)$

$Treat this as if it were: 8 n - 10 = 6 - 2 n$ $color(green)("Treat this as if it were: " 8n-10 =6-2n)$

$In inequalities you have to turn the inequality sign round the other way$ $color(green)("In inequalities you have to turn the inequality sign round the other way")$
$if you multiply by -1. It is NOT THE CASE in this question.$ $color(green)("if you multiply by -1. It is NOT THE CASE in this question.")$
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Add $2 n$ $color(blue)(2n)$ to both sides

$8 n + 2 n - 10 < 6 - 2 n + 2 n$ $" "color(brown)(8ncolor(blue)(+2n)-10 < 6 -2ncolor(blue)(+2n))$

But $- 2 n + 2 n = 0$ $-2n+2n=0$ giving:

$10 n - 10 < 6$ $" "color(brown)(10n-10<6)$

Add $10$ $color(blue)(10)$ to both sides

$10 n + 10 - 10 < 6 + 10$ $" "color(brown)(10ncolor(blue)(+10)-10<6color(blue)(+10))$

$10 n < 16$ $" "color(brown)(10n<16)$

Divide both sides by 10

$\frac{10}{10} n < \frac{16}{10}$ $" "color(brown)(10/(color(blue)(10))n<16/(color(blue)(10))$

But $\frac{10}{10} = 1$ $10/10=1$

$n < 1.6$ $" "color(brown)(n<1.6)$

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Question #9c6b8

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