How to factor #x^2+7x+6#?

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Answer 1 · 2016-12-09T11:03:42

#(x+6)(x+1)#

For this question, we want to find factors, #a, b# where:

#a xx b = 6# and #a + b = 7#

In this case, we can set #a=6, b=1#, which gives us:

#(x+6)(x+1)#

We can show that this works by multiplying it out:

#x xx x = x^2#
#x xx 1 = x#
#6 xx x = 6x#
#6 xx 1 = 6#

and now add them all together:

#x^2+x+6x+6=x^2+7x+6#