Question #8b38a

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Question #8b38a

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Answer 1 · 2017-08-19T17:14:30

24000

Explanation:

There are $_{6} C_{3} = 20$ $""_6C_3 = 20$ ways of selecting 3 boys from the group of 6 boys.
There are $_{5} C_{2} = 10$ $""_5C_2 = 10$ ways of selecting 2 girls from the group of 5 girls.
Therefore, there are $(_{6} C_{3}) \cdot (_{5} C_{2}) = 200$ $(""_6C_3)*(""_5C_2) = 200$ ways of selecting the children.

Once you have selected five children, there are $5! = 120$ $5! = 120$ different orderings of those children.

Therefore, there are $200 \cdot 120 = 24, 000$ $200*120 = 24,000$ ways to both select and order the children.

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Question #8b38a

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