Question

Question #c5f12

Answer 1

N-methylbenzamide

Explanation:

Reduction of N-methylbenzamide with `LiAlH4` gives benzylmethylamine:
`C_6H_5 CONHCH_3` + `LiAlH_4` `->` `C_6H_5 CH_2NHCH_3` + `LiAl(OH)_4`