Question #7a5f8
1 Answer
Dec 17, 2016
Well, once you see that you can convert from
barV = V/n = 22.4 is in"L/mol" , if the standard pressure is"1 atm" and the standard temperature is0^@ "C" .
To get the
11.5 cancel"g Ne" xx "1 mol Ne"/(20.180 cancel"g Ne")
= "0.570 mols Ne"
And the only thing left to do is to get rid of the
"22.4 L"/cancel"mol" xx 0.570 cancel"mols Ne" = color(blue)("12.8 L Ne")
So then, what is the predicted density of