How do you evaluate #lim_(x-> -3) (5x^4 - 3x^2 + 7x)/3#?
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"How do you know a limit does not exist?"
1 Answer
Dec 16, 2016
Explanation:
This can be substituted directly into the function.
#= (5(-3)^4 - 3(-3)^2 + 7(-3))/3#
#=(405 - 27 - 21)/3#
#=119#
Hopefully this helps!
