If $f (2) = 7$ $f(2) = 7$ , and $y = f (x)$ $y = f(x)$ , then what is the value of $p$ $p$ if $p = \frac{1}{f (2)}$ $p = 1/(f(2))$ , rounded to two decimal places?

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If $f (2) = 7$ $f(2) = 7$ , and $y = f (x)$ $y = f(x)$ , then what is the value of $p$ $p$ if $p = \frac{1}{f (2)}$ $p = 1/(f(2))$ , rounded to two decimal places?

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Answer 1 · 2016-12-21T18:03:05

$0.14$ $0.14$

Explanation:

We know that $f (2) = 7$ $f(2) = 7$ . Also, we can rewrite the function as $p = \frac{1}{f (x)}$ $p = 1/f(x)$ . When $x = 2$ $x= 2$ , $f (x) = 7$ $f(x) = 7$ , therefore:

$p = \frac{1}{7}$ $p = 1/7$

$p = 0.14$ $p = 0.14$

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If $f (2) = 7$ $f(2) = 7$ , and $y = f (x)$ $y = f(x)$ , then what is the value of $p$ $p$ if $p = \frac{1}{f (2)}$ $p = 1/(f(2))$ , rounded to two decimal places?

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If f(2)=7f(2) = 7, and y=f(x)y = f(x), then what is the value of pp if p=1f(2)p = 1/(f(2)), rounded to two decimal places?

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If $f (2) = 7$ $f(2) = 7$ , and $y = f (x)$ $y = f(x)$ , then what is the value of $p$ $p$ if $p = \frac{1}{f (2)}$ $p = 1/(f(2))$ , rounded to two decimal places?