Question #7ea2e

1 Answer
Dec 22, 2016

The interacting ratio of number of moles of NH_3 and O_2 as per above equation is 4:5=4/5:1=0.8:1

So if the 1 mole of each reactant here is made to react, O_2 will be fully consumed reacting with 0.8 mole NH_3 and as a result 0.2 mole of NH_3 only will remain as residue.