Question #dd112

Question

Question #dd112

1 Answer

Impact of this question

1227 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-23T21:44:01

There are $24$ $24$ dessert recipies and $48$ $48$ recipies for main dishes.

Explanation:

Reading the problem, I wrote two equations. The first is that $d$ $d$ (dessert) $+ m$ $+ m$ (main) $= 72$ $=72$ . Then, I wrote that $2 d = m$ $2d=m$ , or that there are twice as many dessert recipes as there are main ones.

Now, we use substitution to solve. If $m = 2 d$ $m=2d$ , then we insert $2 d$ $2d$ where $m$ $m$ was, chnaging $d + m = 72$ $d+m=72$ to $d + 2 d = 72$ $d+2d=72$ . This becomes $3 d = 72$ $3d=72$ . By dividing by $3$ $3$ , we see that $d = 24$ $d=24$ .

If $d = 24$ $d=24$ , then $24 + m = 72$ $24+m=72$ . Subtract by $24$ $24$ on both sides, and we just found the value of $m$ $m$ , which is $48$ $48$ . Thus, there are $48$ $48$ main dish recipies and $24$ $24$ dessert dishes.

Science

Math

Humanities

... and beyond

Question #dd112

1 Answer

Explanation:

Related questions

Impact of this question