What is the square root of #3-2sqrt2#? Precalculus Linear and Quadratic Functions Applications of Quadratic Functions 1 Answer Shwetank Mauria Jan 18, 2017 #sqrt(3-2sqrt2)=sqrt2-1# Explanation: #3-2sqrt2# = #2-2sqrt2+1# = #(sqrt2)^2-2xxsqrt2xx1+1^2# = #(sqrt2-1)^2# Hence #sqrt(3-2sqrt2)=sqrt2-1# Answer link Related questions What are common mistakes students make with applications of quadratic functions? How is gravity a quadratic function? How can quadratic equations be used to model ballistics? What is the largest area that can be enclosed by a rectangular fence with a total perimeter of 500 m? In a word problem about ballistics, what do the x-intercepts of a quadratic function represent? In a word problem about ballistics, what does the absolute maximum of a quadratic function represent? How do I solve the formula #16t^2 - 12t - h = 0# for #t#? How do I solve the formula #16t^2 - vt - 40 = 0# for #t#? How do I solve the formula #kx^2 + 8x + 4 = 0# for #x#? If the roots of #2x^2+4x-1=0# are #a# and #b#, find #a^2+b^2#? See all questions in Applications of Quadratic Functions Impact of this question 2886 views around the world You can reuse this answer Creative Commons License