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↳Redirected from "An electron in a hydrogen atom drops from energy level n=5 to n=3. What is the energy transition using the Rydberg equation?"

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Answer 1 · 2017-01-26T17:44:01

The real part is #=5/13#

We need

#(a-b)(a+b)=a^2-b^2#

#i^2=-1#

The conjugate of #(a+ib)# is #(a-ib)#

We multiply numerator and denominator by the conjugate of the denominator

#((4-i)(2-3i))/((2+3i)(2-3i))=(8-12i-2i+3i^2)/(4-9i^2)#

#=(5-14i)/(13)#

#=5/13-14/13i#

The real part is #=5/13#