Question #7c802

Question

Question #7c802

1 Answer

Impact of this question

2643 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-05T13:42:03

Oxides that form neither an acid nor a base, in combination with water.

Explanation:

Acid oxides will react with water to ultimately give off $H^{+}$ $H^+$ :
Sulphur trioxide $S O_{3}$ $SO_3$ will form sulfuric acid:
$S O_{3} (g) + H_{2} O (l) \to H_{2} S O_{4}$ $SO_3 (g) + H_2O (l)->H_2SO_4$ which will give off $H^{+}$ $H^+$

Basic oxides will accept $H^{+}$ $H^+$ :
Calcium oxide $C a O$ $CaO$ will form a base:
$C a O (s) + H_{2} O (l) \to C a {(O H)}_{2}$ $CaO (s)+H_2O(l)->Ca(OH)_2$
The $O H^{-}$ $OH^-$ part combining with $H^{+}$ $H^+$ to form water.
Ferrous oxide $F e O$ $FeO$ will not combine with water, but it will accept $H^{+}$ $H^+$ from an acid:
$F e O + 2 H^{+} \to F e^{2 +} + H_{2} O$ $FeO+2H^+ ->Fe^(2+)+H_2O$

Neutral oxides do neither. Examples are carbon monoxide ( $C O$ $CO$ ), nitrogen monoxide ( $N O$ $NO$ ), and of course water ( $H_{2} O$ $H_2O$ )

Science

Math

Humanities

... and beyond

Question #7c802

1 Answer

Explanation:

Related questions

Impact of this question